If you can encode microstate s in n bits, that implies that you have a prior that assigns P(s)=2^-n. The set of all possible microstates is countably infinite. There is no such thing as a uniform distribution over a countably infinite set. Therefore, even the ignorance prior can't assign equal length bitstrings to all microstates.
If it's worth saying, but not worth its own post (even in Discussion), then it goes here.