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DanielLC comments on Open Thread, Jun. 29 - Jul. 5, 2015 - Less Wrong Discussion

5 Post author: Gondolinian 29 June 2015 12:14AM

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Comment author: DanielLC 29 June 2015 09:53:04AM 0 points [-]

but P(B|A)=1 doesn't imply "A implies B".

Can you give a counterexample?

Comment author: gjm 29 June 2015 12:20:13PM 5 points [-]

A: "X is a random number, uniformly distributed on the interval from 0 to 1."

B: "X is irrational."

Then Pr(B|A) = 1 because almost all numbers are irrational (more formally: because the rationals have measure 0), but A doesn't imply B because X could be rational.

Comment author: Slider 29 June 2015 12:47:21PM 0 points [-]

This could be made to not be a counterexample by using a theory of probability that uses surreals.

That is Pr(irrational|random form 0 to 1) being 1 is of the "almost always" kind, which can be separated form the kind of 1 that is of the "always" kind.

for ω that is larger than any surreal that has a real-counter part, there is a ɛ=1/ω.

Taking only finite samples out of a infinite group makes for a probability that is smaller than any real probability that could well be represented by real/natural multiples of ɛ.

Similarly taking only countably infinite samples from a group of uncountably many samples would result in a probability larger than 0 but smaller than any real value.

Thus we could have P(irrational|between 0 and 1)=1-xɛ and P(rational|between 0 and 1)=xɛ that would sum to exactly 1 and yet P(Z|0-1)=xɛ>0 ie a positive probability.

Similarly the probability of a dart landing exactly on a line in a dart board is "almost never" ie 0 yet that place is as probable as any other location on the dart board. It would be possible to find a dart exactly on the line, you would not just expect to encounter it in a finite number of throws.

However there are counterexamples where all As are indeed Bs but no implication is possible.

Comment author: RichardKennaway 29 June 2015 01:26:40PM 4 points [-]

This could be made to not be a counterexample by using a theory of probability that uses surreals.

Surreal numbers do not yet have a good theory of integration. This makes surreal probability theory problematic.

Comment author: Slider 29 June 2015 10:31:23AM 0 points [-]

Coextensive properties that are not the same property. There are some biological facts like these. Probably not remembering correctly but for example B="animal has heart" A="animal is mammal" it can easily be that all mammals in fact have hearts but you couldn't still say that it would be impossible for a mammal to be heartless (and for example have a blood circulation system that is evenly distributed all over the veins (which they kinda partially do but be totally reliant on those kind of mechanism)). The deduction of "It is a mammal, it must have a heart" is false for plenty of reasonable senses of "must". It is true for the probabilistic sense of must but implication has more senses than the probabilistic one.

Comment author: DanielLC 29 June 2015 08:39:59PM 0 points [-]

If it's a given that all mammals have hearts, then being a mammal implies it has a heart. If it's not known that all mammals have hearts, then P(B|A) < 1.