Lumifer comments on Open Thread - Aug 24 - Aug 30 - Less Wrong Discussion
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Suppose someone offers you the chance to play the following game:
You are given an initial stake of $1. A fair coin is flipped. If the result is TAILS, you keep the current stake. If the result is HEADS, the stake doubles and the coin is flipped again, repeating the process.
How much money should you be willing to pay to play this game?
As formulated, zero -- under the rules you posted you never win anything. Is there an unstated assumption that you can stop the game at any time and exit with your stake?
I guess I didn't formulate the rules clearly enough--if the coin lands on tails, you exit with the stake. For example, if you play and the sequence is HEADS -> HEADS -> TAILS, you exit with $4. The game only ends when tails is flipped.
Also notice that as formulated ("You are given an initial stake of $1") you don't have any of your own money at risk, so... And if the game only ends when TAILS is flipped, there is no way to lose, is there?
If the first $1 comes from you, you are basically asking about the "double till you win" strategy. You might be interested in reading about the St.Petersburg paradox.
Reading the wikipedia article on the St Petersburg paradox, that's exactly the game tetronian2 has described.
Yep. I don't think I was ever aware of the name; someone threw this puzzle at me in a job interview a while ago, so I figured I'd post it here for fun.
The money that's "at stake" is the amount you spend to play the game. Once the game begins, you get 2^(n) dollars, where n is the number of successive heads you flip.