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Not directly. You have to square the velocity of a galaxy, then you must divide it by c (light speed). Then you must divide it by c once again. Then you have to subtract 1, change the sign, compute the square root.
Regardless of the direction of the galaxy in question.
You are very wrong here, I am sorry.
But that's beside the point. We want the right solution and that solution should be in a good agreement with all those Hubble pictures.
Let me try to explain more clearly.
Imagine there are aliens in the high-z galaxy. They produce a laser beam with a particular frequency, pointed at us. There are also other events occurring in their galaxy, for simplicity at the beam source. The aliens measure the time between two events as a particular number of cycles of the laser light.
Now when we observe the laser light and the events, we must also measure the time between the events as the same number of cycles of the laser light apart. But, we see the cycles at a lower frequency by a factor of 1+z, s... (read more)