Actually, you're in a different camp than Laura: she agrees that it's incorrect to two-box regardless of any preference you have about the specified digit of pi. :)
The easiest way to see why two-boxing is wrong is to imagine a large number of trials, with a different chooser, and a different value of i, for each trial. Suppose each chooser strongly prefers that their trial's particular digit of pi be zero. The proportion of two-boxer simulations that end up with the digit equal to zero is no different than the proportion of one-boxer simulations that end up with the digit equal to zero (both are approximately .1). But the proportion of the one-boxer simulations that end up with an actual $1M is much higher (.9) than the proportion of two-boxer simulations that end up with an actual $1M (.1).
The proportion of two-boxer simulations that end up with the digit equal to zero is no different than the proportion of one-boxer simulations that end up with the digit equal to zero (both are approximately .1). But the proportion of the one-boxer simulations that end up with an actual $1M is much higher (.9) than the proportion of two-boxer simulations that end up with an actual $1M (.1).
But the proportion of two-boxers that saw $1M in the box that end up
is even higher (1). I already saw the $1M, so, by two-boxing, aren't I just choosing to be one of those who see their E module output True?
According to Ingredients of Timeless Decision Theory, when you set up a factored causal graph for TDT, "You treat your choice as determining the result of the logical computation, and hence all instantiations of that computation, and all instantiations of other computations dependent on that logical computation", where "the logical computation" refers to the TDT-prescribed argmax computation (call it C) that takes all your observations of the world (from which you can construct the factored causal graph) as input, and outputs an action in the present situation.
I asked Eliezer to clarify what it means for another logical computation D to be either the same as C, or "dependent on" C, for purposes of the TDT algorithm. Eliezer answered:
I replied as follows (which Eliezer suggested I post here).
If that's what TDT means by the logical dependency between Platonic computations, then TDT may have a serious flaw.
Consider the following version of the transparent-boxes scenario. The predictor has an infallible simulator D that predicts whether I one-box here [EDIT: if I see $1M]. The predictor also has a module E that computes whether the ith digit of pi is zero, for some ridiculously large value of i that the predictor randomly selects. I'll be told the value of i, but the best I can do is assign an a priori probability of .1 that the specified digit is zero.