the output of C also causes the predictor to choose a suitable i
How's that? Any i that is sufficiently large is suitable. It doesn't depend on the output of C. It just needs to be beyond C's ability to learn anything beyond the ignorance prior regarding the i-th digit of π.
I've finally figured out where my intuition on that was coming from (and I don't think it saves TDT). Suppose for a moment you were omniscient except about the relative integrals Vk (1) over measures of the components of the wavefunction which
Here my ignorance prior on pi[x] for large values of x happens to be approximately equivalent to your ignorance p...
According to Ingredients of Timeless Decision Theory, when you set up a factored causal graph for TDT, "You treat your choice as determining the result of the logical computation, and hence all instantiations of that computation, and all instantiations of other computations dependent on that logical computation", where "the logical computation" refers to the TDT-prescribed argmax computation (call it C) that takes all your observations of the world (from which you can construct the factored causal graph) as input, and outputs an action in the present situation.
I asked Eliezer to clarify what it means for another logical computation D to be either the same as C, or "dependent on" C, for purposes of the TDT algorithm. Eliezer answered:
I replied as follows (which Eliezer suggested I post here).
If that's what TDT means by the logical dependency between Platonic computations, then TDT may have a serious flaw.
Consider the following version of the transparent-boxes scenario. The predictor has an infallible simulator D that predicts whether I one-box here [EDIT: if I see $1M]. The predictor also has a module E that computes whether the ith digit of pi is zero, for some ridiculously large value of i that the predictor randomly selects. I'll be told the value of i, but the best I can do is assign an a priori probability of .1 that the specified digit is zero.