Comment author: Mitchell_Porter 16 December 2011 04:27:45AM 2 points [-]

"The error" could mean: the false thing that is being asserted; the reason why it is false; or the cognitive mistake which allows it to escape detection.

Maybe I should begin with the true thing that is being asserted! Which is that the number of ink blots can depend on definition, or on the judgment or whim of the individual observer. That is indeed true.

It also may or may not be true that the number of branches, worlds, blobs, etc., in a wavefunction is similarly undefined, or dependent on a somewhat arbitrary definition.

What I deem to be categorically false is the proposition that this is also true of "observers", or "portions of reality that can contain observers" (which might be called worlds or branches), or even just "portions of reality like the one that I find myself in" (which is a definition not involving observers, except incidentally).

The reason that this is false, is that the arbitrariness of the number of blobs, arises from the arbitrariness of their definition. Their very existence is in some sense arbitrary, relative, observer-dependent. It is because their existence is relative, that their number is relative.

The existence of the observed portion of reality is not "relative"; it is definitely there, and it is not caused by the contingent and changeable decisions of some observer about how to divide up reality. On the contrary, the observer here is part of the branch or world; their role is simply to register the fact that it exists, not to have created it.

Why isn't this reasoning used to criticize and rule out theories in which the existence of worlds and branches is vague and definition-dependent? This is what the post is actually about. At some level, it must be nothing more than a failure to combine fact A (this interpretation says worlds in the wavefunction are vague) with fact B (the existence of the real world can't be vague) in order to draw the obvious conclusion (this interpretation must be wrong). But how does this work psychologically? I was hoping some believers in the "Oxford school" would describe how they arrived at their belief, but it seems I first have to communicate why this belief is so problematic.

Comment author: Mallah 18 April 2012 09:25:57PM -1 points [-]

Mitchell, you are on to an important point: Observers must be well-defined.

Worlds are not well-defined, and there is no definite number of worlds (given standard physics).

You may be interested in my proposed Many Computations Interpretation, in which observers are identified not with so-called 'worlds' but with implementations of computations: http://arxiv.org/abs/0709.0544

See my blog for further discussion: http://onqm.blogspot.com/

Comment author: pjeby 18 May 2010 06:29:28PM 4 points [-]

Acting without apparent fear of the consequences, even stupidly, is often respected as long as you get away with it.

But you didn't get away with it.

Also, technically, you acted like a creep, not a jerk. (A jerk acts boldly, a creep is sneaky and opportunistic.)

Comment author: Mallah 19 May 2010 02:35:13PM 0 points [-]

I wasn't sneaky about it.

Comment author: Vladimir_M 17 May 2010 08:16:13PM *  9 points [-]

Other people (that I have talked to) seem to be divided on whether it was a good thing to do or not.

It sure was one hell of a low status signal. The worst possible way you can fail a shit test is to get visibly hurt and angry.

As for whether she deserved it, well, if you want to work in the kitchen, better be prepared to stand the heat. Expecting women you hit on to follow the same norms of behavior as your regular buddies and colleagues, and then getting angry when they don't, is like getting into a boxing match and then complaining you've been assaulted.

Comment author: Mallah 18 May 2010 03:48:57PM -1 points [-]

I don't think I got visibly hurt or angry. In fact, when I did it, I was feeling more tempted than angry. I was in the middle of a conversation with another guy, and her rear appeared nearby, and I couldn't resist.

It made me seem like a jerk, which is bad, but not necessarily low status. Acting without apparent fear of the consequences, even stupidly, is often respected as long as you get away with it.

Another factor is that this was a 'high status' woman. I'm not sure but she might be related to a celebrity. (I didn't know that at the time.) Hence, any story linking me and her may be 'bad publicity' for me but there is the old saying 'there's no such thing as bad publicity'.

Comment author: NancyLebovitz 15 May 2010 10:24:34PM 3 points [-]

You assaulted her because she asked for an expensive drink, you gave her the drink, and then she ignored you?

You say you don't recommend what you did, but I'm curious about why, considering that you seem to think she deserved it.

Comment author: Mallah 17 May 2010 02:21:04PM 4 points [-]

It was a single swat to the buttocks, done in full sight of everyone. There was other ass-spanking going on, between people who knew each other - done as a joke - so in context it was not so unusual. I would not have done it outside of that context, nor would I have done it if my inhibitions had not been lowered by alcohol; nor would I do it again even if they are.

Yes, she deserved it!

It was a mistake. Why? It exposed me to more risk than was worthwhile, and while I might have hoped that (aside from simple punishment) it would teach her the lesson that she ought to follow the Golden Rule, or at least should not pull the same tricks on guys, in retrospect it was unlikely to do so.

Other people (that I have talked to) seem to be divided on whether it was a good thing to do or not.

Comment author: CronoDAS 14 May 2010 05:24:42PM *  3 points [-]

There are also some reliable proxies of fitness that are no longer reliable, for example height (can be modified by higher shoes - a trick that women have cottoned on to, but men are totally missing out on).

Not entirely, although there does seem to be some shame attached to doing this.

I do much the same thing by wearing hiking boots everywhere. They're waterproof, well-insulated for cold weather, and also increase my height more than sneakers.

Comment author: Mallah 15 May 2010 10:33:01PM 2 points [-]

Women seem to have a strong urge to check out what shoes a man has on, and judge their quality. Even they can't explain it. Perhaps at some unconscious level, they are guarding against men who 'cheat' by wearing high heels.

Comment author: RichardKennaway 14 May 2010 05:51:14PM 7 points [-]

After a short time, they ask you to buy them a drink.

I have never encountered or heard of this behaviour. I would be rather startled if someone I had just met asked me to buy them a drink. I'd guess they were too poor to get their own (and with all respect to poor people, my interest in pursuing a relationship with them would substantially diminish).

I can understand your explanation, but I would find an opposite explanation just as plausible (they are trying to determine if the cost of a drink is a mere trifle to you, hence buying them one = good).

Is this a culturally specific thing? Where is this action, with this meaning, a standard pattern of behaviour?

Comment author: Mallah 15 May 2010 09:38:54PM *  0 points [-]

I can confirm that this does happen at least sometimes (USA). I was at a bar, and I approached a woman who is probably considered attractive by many (skinny, bottle blonde) and started talking to her. She soon asked me to buy her a drink. Being not well versed in such matters, I agreed, and asked her what she wanted. She named an expensive wine, which I agreed to get her a glass of. She largely ignored me thereafter, and didn't even bother taking the drink!

(I did obtain some measure of revenge later that night by spanking her rear end hard, though I do not advise doing such things. She was not amused and her brother threatened me, though as I had apologized, that was the end of it. She did tell some other lies so I don't know if she is neurotypical; my impression was that she was well below average in morality, being a spoiled brat.)

Comment author: cupholder 16 April 2010 09:09:01PM 0 points [-]

If that were the case, the camera might show the person being killed; indeed, that is 50% likely.

Yep. But Stuart_Armstrong's description is asking us to condition on the camera showing 'you' surviving.

Pre-selection is not the same as our case of post-selection. My calculation shows the difference it makes.

It looks to me like we agree that pre-selecting someone who happens to survive gives a different result (99%) to post-selecting someone from the pool of survivors (50%) - we just disagree on which case SA had in mind. Really, I guess it doesn't matter much if we agree on what the probabilities are for the pre-selection v. the post-selection case.

Now, if the fraction of observers of each type that are killed is the same, the difference between the two selections cancels out. That is what tends to happen in the many-shot case, and we can then replace probabilities with relative frequencies.

I am unsure how to interpret this...

One-shot probability is not relative frequency.

...but I'm fairly sure I disagree with this. If we do Bernoulli trials with success probability p (like coin flips, which are equivalent to Bernoulli trials with p = 0.5), I believe the strong law of large numbers implies that the relative frequency converges almost surely to p as the number of Bernoulli trials becomes arbitrarily large. As p represents the 'one-shot probability,' this justifies interpreting the relative frequency in the infinite limit as the 'one-shot probability.'

Comment author: Mallah 18 April 2010 04:35:54PM *  0 points [-]

But Stuart_Armstrong's description is asking us to condition on the camera showing 'you' surviving.

That condition imposes post-selection.

I guess it doesn't matter much if we agree on what the probabilities are for the pre-selection v. the post-selection case.

Wrong - it matters a lot because you are using the wrong probabilities for the survivor (in practice this affects things like belief in the Doomsday argument).

I believe the strong law of large numbers implies that the relative frequency converges almost surely to p as the number of Bernoulli trials becomes arbitrarily large. As p represents the 'one-shot probability,' this justifies interpreting the relative frequency in the infinite limit as the 'one-shot probability.'

You have things backwards. The "relative frequency in the infinite limit" can be defined that way (sort of, as the infinite limit is not actually doable) and is then equal to the pre-defined probability p for each shot if they are independent trials. You can't go the other way; we don't have any infinite sequences to examine, so we can't get p from them, we have to start out with it. It's true that if we have a large but finite sequence, we can guess that p is "probably" close to our ratio of finite outcomes, but that's just Bayesian updating given our prior distribution on likely values of p. Also, in the 1-shot case at hand, it is crucial that there is only the 1 shot.

Comment author: Academian 16 April 2010 06:08:41PM *  0 points [-]

Is that a "yes" or a "no" for the scenario as I posed it?

The way you set up the decision is not a fair test of belief.

I agree. It is only possible to fairly "test" beliefs when a related objective probability is agreed upon, which for us is clearly a problem. So my question remains unanswered, to see if we disagree behaviorally:

the stakes are more like $1.50 to $99.

That's not my intention. To clarify, assume that:

  • the other prisoners' decisions are totally independent of yours (perhaps they are irrational), so that you can in no sense effect 99 real other people to guess blue and achieve a $99 payoff with only one beating, and

  • the payoffs/beatings are really to the prisoners, not someone else,

Then, as I said, in that scenario I would guess that I'm in a blue room.

Would you really guess "red", or do we agree?

(My "reasons" for blue would be to note that I started out overwhelmingly (99%) likely to be in a blue room, and that my surviving the subsequent coin toss is evidence that it did not land tails and kill blue-roomed prisoners, or equivalently, that counterfactual-typically, people guessing red would result in a great deal of torture. But please forget why; I just want to know what you would do.)

Comment author: Mallah 18 April 2010 04:22:02PM 0 points [-]

It is only possible to fairly "test" beliefs when a related objective probability is agreed upon

That's wrong; behavioral tests (properly set up) can reveal what people really believe, bypassing talk of probabilities.

Would you really guess "red", or do we agree?

Under the strict conditions above and the other conditions I have outlined (long-time-after, no other observers in the multiverse besides the prisoners), then sure, I'd be a fool not to guess red.

But I wouldn't recommend it to others, because if there are more people, that would only happen in the blue case. This is a case in which the number of observers depends on the unknown, so maximizing expected average utility (which is appropriate for decision theory for a given observer) is not the same as maximizing expected total utility (appropriate for a class of observers).

More tellingly, once I find out the result (and obviously the result becomes known when I get paid or punished), if it is red, I would not be surprised. (Could be either, 50% chance.)

Not that I've answered your question, it's time for you to answer mine: What would you vote, given that the majority of votes determines what SB gets? If you really believe you are probably in a blue room, it seems to me that you should vote blue; and it seems obvious that would be irrational.

Then if you find out it was red, would you be surprised?

Comment author: Academian 16 April 2010 10:16:42AM *  1 point [-]

I have been attacking it by deriving the right answer from general considerations (that is, P(tails) = 1/2 for the 1-shot case

Let me instead ask a simple question: would you actually bet like you're in a red room?

Suppose you were told the killing had happened (as in the right column of Cupholder's diagram, and required to guess the color of your room, with the following payoffs:

  • Guess red correctly -> you earn $1.50

  • Guess blue correctly -> you earn $1.00

  • Guess incorrectly -> you are terribly beaten.

Would you guess red? Knowing that under independent repeated or parallel instances of this scenario (although merely hypothetical if you are concerned with the "number of shots"),

  • "guess heads" mentality typically leads to large numbers of people (99%) being terribly beaten

  • "guess blue" mentality leads to large numbers of people (99%) earning $1 and not being beaten

  • this not an interactive scenario like the Prisoner's dilemma, which is interactive in a way that renders a sharp distinction between group rationality and individual rationality,

would you still guess "red"? Not me. I would take my survival as evidence that blue rooms were not killed, and guess blue.

If you would guess "blue" for "other reasons", then we would exhibit the same behavior, and I have nothing more to discuss. At least in this case, our semantically different ways of managing possibilities are resulting in the same decision, which is what I consider important. You may disagree about this importance, but I apologize that I'm not up for another comment thread of this length.

If you would really guess "red", then I have little more to say than to reconsider your actions, and to again excuse me from this lengthy discussion.

Comment author: Mallah 16 April 2010 04:06:44PM *  0 points [-]

The way you set up the decision is not a fair test of belief, because the stakes are more like $1.50 to $99.

To fix that, we need to make 2 changes:

1) Let us give any reward/punishment to a third party we care about, e.g. SB.

2) The total reward/punishment she gets won't depend on the number of people who make the decision. Instead, we will poll all of the survivors from all trials and pool the results (or we can pick 1 survivor at random, but let's do it the first way).

The majority decides what guess to use, on the principle of one man, one vote. That is surely what we want from our theory - for the majority of observers to guess optimally.

Under these rules, if I know it's the 1-shot case, I should guess red, since the chance is 50% and the payoff to SB is larger. Surely you see that SB would prefer us to guess red in this case.

OTOH if I know it's the multi-shot case, the majority will be probably be blue, so I should guess blue.

In practice, of course, it will be the multi-shot case. The universe (and even the population of Earth) is large; besides, I believe in the MWI of QM.

The practical significance of the distinction has nothing to do with casino-style gambling. It is more that 1) it shows that the MWI can give different predictions from a single-world theory, and 2) it disproves the SIA.

Comment author: cupholder 15 April 2010 11:14:55PM 0 points [-]

I'll try to clarify what I'm thinking of as the relevant kind of selection in this exercise. It is true that the condition effectively picks out - that is, selects - the probability branches in which 'you' don't die, but I don't see that kind of selection as relevant here, because (by my calculations, if not your own) it has no impact on the probability of being behind a blue door.

What sets your probability of being behind a blue door is the problem specifying that 'you' are the experimental subject concerned: that gives me the mental image of a film camera, representing my mind's eye, following 'you' from start to finish - 'you' are the specific person who has been selected. I don't visualize a camera following a survivor randomly selected post-killing. That is what leads me to think of the relevant selection as happening pre-killing (hence 'pre-selection').

Comment author: Mallah 16 April 2010 03:46:25PM 0 points [-]

If that were the case, the camera might show the person being killed; indeed, that is 50% likely.

Pre-selection is not the same as our case of post-selection. My calculation shows the difference it makes.

Now, if the fraction of observers of each type that are killed is the same, the difference between the two selections cancels out. That is what tends to happen in the many-shot case, and we can then replace probabilities with relative frequencies. One-shot probability is not relative frequency.

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