Johnicholas comments on LW/OB Quotes - Fall 2009 - Less Wrong

2 Post author: thomblake 01 September 2009 03:11PM

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Comment author: Johnicholas 15 September 2009 12:29:10PM 0 points [-]

There's a flaw in your proof - the step from "The machine will necessarily stop" to "This solves the halting problem" is unjustified.

Despite the flaw, I agree with your general conclusion - there are and will be challenging as well as unsolvable problems.

Comment author: pengvado 15 September 2009 08:10:31PM *  3 points [-]

It's justified. If a machine halts, then there's a proof of that in PA (simply the list of steps it performs before halting). Therefore, "independent of PA" implies "doesn't halt". Therefore, a provability decider is the same as a halting decider.

Comment author: Johnicholas 15 September 2009 11:31:13PM 1 point [-]

With the added steps, yes, there is a proof.