= 27d567bc2d48d9f40e9ccc20ea370b15)
prase comments on Open Thread June 2010, Part 3 - Less Wrong
You are viewing a comment permalink. View the original post to see all comments and the full post content.
= 783df68a0f980790206b9ea87794c5b6)
Loading…= b715d02e85f7b3b4ae65ca3d3e450868)
Subscribe to RSS Feed
Powered by Reddit
= f037147d6e6c911a85753b9abdedda8d)
You are viewing a comment permalink. View the original post to see all comments and the full post content.
Comments (606)
But still, in the rotating scenario the attractive force wouldn't be perpendicular to the planet's surface, and this can be established without knowing the gravitational constant. If the planet is spherical and you already know what is perpendicular, of course.