# PhilGoetz comments on The bias shield - Less Wrong

18 31 December 2011 05:44PM

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Comment author: 03 January 2012 11:29:29PM 0 points [-]

You're right - using 1/distance makes all the weight come from the immediate neighborhood. I don't think it's a fatal problem. That's not why the effect is strongest at the edges. The addition of s(w) makes it work out that way.

I'm not following the bit about maximum product of radius^3*opinion density. Is that something that came out after integrating? I've thrown my work out by now, so can't check without redoing it.

The simplest w(v) is w(v) = v. The s(w) proposed is |w|. a(w(pi),w(pj))(1 + s(w(vj))(vi·vj)) when pj = <x, 0> is a(pi, <x,0>)(1 + |vj|)(vi · <x,0>) = (1+x)*x*xi / [(xi - x)^2 + yi^2]. The problem with x_i being close to x is the same everywhere in the plane.

Comment author: 04 January 2012 09:08:45PM 0 points [-]

You're right - using 1/distance makes all the weight come from the immediate neighborhood. I don't think it's a fatal problem. That's not why the effect is strongest at the edges. The addition of s(w) makes it work out that way.

Right, that alone doesn't make it strongest at the edges. It just means that you're measuring how strongly a tiny few people agree, not how believable it is to any significant fraction of people, and it didn't come across to me as clearly marked as such.