= 27d567bc2d48d9f40e9ccc20ea370b15)
paper-machine comments on New Monthly Thread: Bragging - Less Wrong
You are viewing a comment permalink. View the original post to see all comments and the full post content.
= 783df68a0f980790206b9ea87794c5b6)
Loading…= b715d02e85f7b3b4ae65ca3d3e450868)
Subscribe to RSS Feed
Powered by Reddit
= f037147d6e6c911a85753b9abdedda8d)
You are viewing a comment permalink. View the original post to see all comments and the full post content.
Comments (145)
A number mod 10^n yields the last n digits of the number.
Aaah. it was just saying how much to output. Phew. I was trying to figure out what 10^80 could have to do with 3^^^3 and failing, hard. So, it's a great relief that the answer is, 'nothing'.
Technically, I have not used the fact that the number in question is 3^^^3 -- I am treating it as 3^^X, where X is very large. So for huge numbers of digits, this will not give the correct answer, but I don't think it's practical to compute that many digits, in any case.
Should I explain how everything else works?
Nah, I just figured that the named functions were something relevant, and I'm satisfied with that level of knowledge at this point.