Ishaan comments on The Ultimate Newcomb's Problem - Less Wrong

18 Post author: Eliezer_Yudkowsky 10 September 2013 02:03AM

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Comment author: Ishaan 10 September 2013 04:38:46PM *  0 points [-]

Maybe I'm confused, but can't it just... pick one however it wants? As long as the final tally comes to "correct in 99.9% of cases" the problem is satisfied and it doesn't matter how it decided, does it? Why does it matter if there are muliple correct choices?

Edit: Nevermind, I see what you mean. If your algorithm depends on the Lotto, and Omega depends on your algorithm, then Omega depends on the Lotto. You can actually influence how often this "same number" scenario happens via your algorithm.