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ArisKatsaris comments on The Ultimate Newcomb's Problem - Less Wrong
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Both boxes -- I want the number to be composite, so I want Omega to have selected a composite number, which he'd have more chances of doing if I two-boxed.
EDIT: wedrifid's explanation has now mostly convinced me that one-boxing is correct instead. (My expressed logic was too much EDT-influenced, I think)
You want the number to be composite, so you also want the Numerical Lottery's random number generator to have selected a composite number. That's trickier to influence.