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Mark_Friedenbach comments on Open Thread, Feb. 2 - Feb 8, 2015 - Less Wrong Discussion
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I'm pretty sure Manfred is right. You drop a block of ice of unknown configuration into a cup of tea of known configuration, then your uncertainty about the system will grow over time. Of course entropy != temperature. You coudl say that the tea has zero entropy, but not zero temperature.
But what's the point of this thought exercise?
The block of ice is not of unknown configuration. The block of ice in my example is at 0 K, which means it has zero entropy (all molecules rigidly locked in a regular periodic lattice) and thus its configuration is completely known.