MrMind comments on Open thread, Mar. 23 - Mar. 31, 2015 - Less Wrong Discussion
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Eh, not really. You're still bounded by the finite cosmological horizon. Unless of course you have access to super-luminal travel.
Exactly.
It depends. If you use "subsets" as a generative ontological procedure, you would still be stuck by the finite time of the operation. If you consider "subset" instead as a conceptual relation, not some concrete process, you're not stuck in any cardinal.
No. Once you postulate a countable cardinal, you get for free ordinals like "omega plus one", "omega plus two", etc. And since uncountable cardinals are ordered by ordinals, you also get for free more than omega uncountable cardinals.
Inaccessible is the next quantity for which you need a new axiom. Indeed, "inaccessible" is the quantity of cardinals generated in the process above.