Last year, AlexMennen ran a prisoner's dilemma tournament with bots that could see each other's source code, which was dubbed a "program equilibrium" tournament. This year, I will be running a similar tournament. Here's how it's going to work: Anyone can submit a bot that plays the iterated PD against other bots. Bots can not only remember previous rounds, as in the standard iterated PD, but also run perfect simulations of their opponent before making a move. Please see the github repo for the full list of rules and a brief tutorial.
There are a few key differences this year:
1) The tournament is in Haskell rather than Scheme.
2) The time limit for each round is shorter (5 seconds rather than 10) but the penalty for not outputting Cooperate or Defect within the time limit has been reduced.
3) Bots cannot directly see each other's source code, but they can run their opponent, specifying the initial conditions of the simulation, and then observe the output.
All submissions should be emailed to pdtournament@gmail.com or PM'd to me here on LessWrong by September 15th, 2014. LW users with 50+ karma who want to participate but do not know Haskell can PM me with an algorithm/psuedocode, and I will translate it into a bot for them. (If there is a flood of such requests, I would appreciate some volunteers to help me out.)
Transparent tit-for-tat is a decent enough strategy, but it is easily beaten 1-on-1 by "cooperate on every turn except the very last one", and against many other simple bots by "TFT but defect on the last turn".
That being said, when the game is 100 turns long, it's pretty hard to do significantly better than Tit-for-Tat - the aforementioned strategies only beat TFT with a score of 302-297.
I think that's probably a good reason to shorten the round length from 100 down to, say, 10 or 20 - otherwise the variance from a single RandomBot would drown out that score difference.
I agree, I was simply giving an example of a strategy which would not lead to the sort of infinite regress envisioned by ThisSpaceAvailable.
I do think it's worth noting that "TFT but defect on the last turn" would be beaten 1-on-1 by "TFT but defect on the last two turns." And both of them would be beate... (read more)