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In Professor Jaynes’ theory of probability, probability is the degree of plausibility about a thing given some knowledge and not an physical property of that thing.

However, I see people treating the probability of heads in a coin flip as a parameter that needs to be estimated. Even Professor Jaynes gives the impression that he is “estimating the probability” or looking for “the most plausible probability of heads” in page 164 of his book.

How does the idea of ”estimating a probability from data“ or finding the “most probable probability of heads in a coin flip given some data” make sense from this paradigm?

Thank you for your time

ET JaynesMind Projection FallacyProbabilistic ReasoningProbability & StatisticsRationalityAI
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Jaynesian interpretation - How does “estimating probabilities” make sense?
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deepthoughtlife

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I don't know the theory itself, but from your description it seems likely that it is a simple ease of thinking thing. 'What should I believe is the likelihood that the result of a coinflip is heads?' isn't any different in meaning than 'estimating the probability of heads from data' or 'how plausible is heads?' as far as our actions go. We have formal ways of doing the middle of the three easily, so it is easier to think of that way, and we have built up intuitions about coinflips that require it.

Whether or not it is a physical property, it is easier to describe properties of individual things rather than of large combinations of things and actions. If his description of how the evidence should be weighed includes large parts of his theory, it could still be a valuable example.

[-]Dagon30

That's my take as well.  "estimating the probability" really means "calculating the plausibility based on this knowledge".

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1[anonymous]
I believe, mathematically, your claim can be expressed as:  P(H|D) = argmaxθP(θ|D) where θ is the ”probability“ parameter of the Bernoulli distribution, H represents the the proposition that heads occurs, and D represents our data. The left side of this equation is the plausibility based on knowledge and the right side is Professor Jaynes’ ‘estimate of the probability’ . How can we prove this statement? Edit: Latex is being a nuisance as usual :) The right side of the equation is the argmax with respect to theta of P(theta | data)
2Jan Christian Refsgaard
I think argmax is not the way to go as the beta distribution and binomial likelihood is only symmetric when the coin is fair, if you want a point estimate the mean of the distribution is better, which will always be closer to 50/50 than the mode, and thus more conservative, you are essentially ignoring all the uncertainty of theta and thus overestimating the probability.
1[anonymous]
What is the theoretical justification behind taking the mean? Argmax feels more intuitive for me because it is literally “the most plausible value of theta”. In either case, whether we use argmax or mean, can we prove that it is equal to P(H|D)? 
1Jan Christian Refsgaard
If I have a distribution of 2 kids and a professional boxer, and a random one is going to hit me, then argmax tells me that I will always be hit by a kids, sure if you draw from the distribution only once then argmax will beat the mean in 2/3 of the cases, but its much worse at answering what will happen if I draw 9 hits (argmax=nothing, mean=3hits from a boxer) This distribution is skewed, like the beta distribution, and is therefore better summarized by the mean than the mode. In Bayesian statistics argmax on sigma will often lead to sigma=0, if you assume that sigma follows a exponential distribution, thus it will lead you to assume that there is no variance in your sample The variance is also lower around the mean than the mode if that counts as a theoretical justification :)
[-]Jan Christian Refsgaard20

Disclaimer: Subjective Bayesian
 

Here is how we evil subjective Bayesian think about it

Prior:

Lets imagine two people, Janes and an Alien, Janes knows that most coins are fair and has a Beta(20, 20) prior, the alien does not know this, and puts the 'objective' Beta(1, 1) prior which is uniform for all frequencies.

Data:

The data comes up 12 heads and 8 tails

Posterior:

Janes has a narrow posterior Beta(32, 28) and the alien a broader Beta(13, 9), Janes posterior is also close to 50/50

if Janes does not have access to the data that formed his prior or cannot ... (read more)

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2[anonymous]
I am very grateful for your answer but I have a few contentions from my paradigm of objective Bayesianism 1. You have replaced probability with a physical property: “frequency“. I have also seen other people use terms like bias-weighting, fairness, center of mass, etc. which are all properties of the coin, to sidestep this question. I have nothing against theta being a physical property such that P(heads|theta=alpha) = alpha. In fact, it would make a ton of sense to me if this actually were the case. But the issue is when people say that theta is a probability and treat it as if it was a physical property. I presume you don’t view probabilities to be physical properties. Even subjective Bayesians are not that evil... 2. “if Janes does not have access to the data that formed his prior or cannot explain it well, then what he believes about the coin and what the alien believes about the coin are both 'rational', as it is the posterior from their personal priors and the shared data.” If Professor Jaynes did not have access to the data that formed his prior, his prior would have been the same as the alien’s and they would have ended up with the same posterior. There is no such thing as a “personal prior”. I invite you to the light side: read Professor Jaynes’ book; it is absolutely brilliant
2Jan Christian Refsgaard
I may be to bad at philosophy to give a satisfying answer, and it may turn out that I actually do not know and am simply to dumb to realize that I should be confused about this :) 1. There is a frequency of the coin in the real world, let's say it has θ=0.5 1. Because I am not omniscient there is a distribution over θ  it's parameterized by some prior which we ignore (let's not fight about that :)) and some data x, thus In my head there exists a probability distribution p(θ∣x) 2. The probability distribution on my head is a distribution not a scaler, I don't know what θ is but I may be 95% certain that it's between 0.4 and 0.6  2. I think there are problems with objective priors, but I am honored to have meet an objective Bayesian in the wild, so I would love to try to understand you, I am Jan Christian Refsgaard on the University of Bayes and Bayesian conspiracy discord servers. My main critique is the 'in-variance' of some priors under some transformations, but that is a very weak critique and my epistemology is very underdeveloped, also I just bought Jaynes book :) and will read when I find a study group, so who knows maybe I will be an objective Bayesian a year from now :)
2[anonymous]
Response to point one: I do find that to be satisfactory from a philosophical perspective but only because theta refers to a real-world property called frequency and not the probability of heads. My question to you is this: if you have a point estimate of theta or if you find the exact real world-value of theta (perhaps by measuring it with an ACME frequency-o-meter), what does it tell you about the probability of heads? Response to point two: The honour is mine :) If you ever create a study group or discord server for the book, then please count me in
2Jan Christian Refsgaard
In Bayesian statistics there are two distributions which I think we are conflating here because they happen to have the same value The posterior p(θ∣y) describes our uncertainty of θ, given data (and prior information), so it's how sure we are of the frequency of the coin The posterior predictive is our prediction for new coin flips ~y given old coin flips y   p(~y|y)=∫Θp(~y∣θ,y)p(θ∣y)dθ For the simple Bernoulli distribution coin example, the following issue arise: the parameter θ, the posterior predictive and the posterior all have the same value, but they are different things. Here is an example were they are different: Here θ was not a coin but the logistic intercept of some binary outcome with predictor variable x, let's imagine an evil Nazi scientist poisoning people, then we could make a logistic model of y (alive/dead) such as y=invlogit(ax+logit(θ)), Let's imagine that x is how much poison you ate above/below the average poison level, and that we have θ=0.5, so on average half died Now we have: the value if we were omniscient θ=0.5 The posterior of θ because we are not omniscient there is error p(θ|y)=0.5+ϵ Predictions for two different y with uncertainty: p(~ylots of poison∣y)=p(~y∣y,~x=2)=0.99±ϵ≈0.99p(~yaverage poison∣y)=p(~y∣y,~x=0)=0.5±ϵ≈0.5 Does this help?   I will PM you when we start reading Jaynes, we are currently reading Regression and other stories, but in about 20 weeks (done if we do 1 chapter per week) there is a good chance we will do Jaynes
2[anonymous]
To calculate the posterior predictive you need to calculate the posterior and to the calculate posterior you need to calculate the likelihood (in most problems). For the coin flipping example, what is the probability of heads and what is the probability of tails given that the frequency is equal to some value theta? You might accuse me of being completely devoid of intuition for asking this question but please bear with me... Sounds good. I thought nobody was interested in reading Professor Jaynes’ book anymore. It’s a shame more people don’t know about him
2Jan Christian Refsgaard
Regarding reading Jaynes, my understanding is its good for intuition but bad for applied statistics because it does not teach you modern bayesian stuff such as WAIC and HMC, so you should first do one of the applied books. I also think Janes has nothing about causality.
1[anonymous]
I‘m afraid I have to disagree. I do sometimes regret not focusing more on applied Bayesian inference. (In fact, I have no idea what WAIC or HMC is.) But in my defence, I am an amateur analytical-philosopher & logician and I couldn’t help finding more non-sequiturs in classical expositions of probability theory than plot-holes in Tolkien novels. Perhaps if had been more naive and less critical (no offence to anyone) when I read those books, I would have “progressed” faster. I had lost hope in understanding probability theory before I read Professor Jaynes’ book; that’s why I respect the man so much. Now I have the intuition but I am still trying to reconcile it with what I read in the applied literature. I sometimes find it frustrating that I am worrying about the philosophical nuances and intricacies of probability theory while others are applying their (perhaps less coherent) understanding of it to solve problems but I strongly believe it is worth it :)
2Jan Christian Refsgaard
I am one of those people with an half baked epistemology and understanding of probability theory, and I am looking forward to reading Janes. And I agree there are a lot of ad hocisms in probability theory which means everything is wrong in the logic sense as some of the assumptions are broken, but a solid moden bayesian approach has much less adhocisms and also teaches you to build advanced models in less than 400 pages. HMC is a sampling approach to solving the posterior which in practice is superior to analytical methods, because it actually accounts for correlations in predictors and other things which are usually assumed away. WAIC is information theory on distributions which allows you to say that model A is better than model B because the extra parameters in B are fitting noice, basically minimum description length on steroids for out of sample uncertainty. Also I studied biology which is the worst, I can perform experiments and thus do not have to think about causality and I do not expect my model to acout for half of the signal even if it's 'correct'
2Jan Christian Refsgaard
Given 1. your model and 2 the magical no uncertainty in theta, then it's theta, the posterior predictive allows us to jump from infrence about parameters to infence about new data, it's a distribution of y (coin flip outcomes) not theta (which describes the frequency)
2[anonymous]
Think I have finally got it. I would like to thank you once again for all your help; I really appreciate it.  This is what I think “estimating the probability” means: We define theta to be a real-world/objective/physical quantity s.t. P(H|theta=alpha) = alpha & P(T|theta=alpha) = 1 - alpha. We do not talk about the nature of this quantity theta because we do not care what it is. I don’t think it is appropriate to say that theta is “frequency” for this reason: 1. “frequency” is not a well-defined physical quantity. You can’t measure “frequency” like you measure temperature. But we do not need to dispute about this as theta being “frequency” is unnecessary. Using the above definitions, we can compute the likelihood and then the posterior and then the posterior predictive which is represents the probability of heads in the next flip given data from previous flips. Is the above accurate? So Bayesians who say that theta is the probability of heads and compute a point estimate of the parameter theta and say that they have “estimated the probability” are just frequentists in disguise?
2Jan Christian Refsgaard
I think the above is accurate.    I disagree with the last part, but it has two sources of confusion 1. Frequentists vs Bayesian is in principle about priors but in practice about about point estimates vs distributions 1. Good Frequentists use distributions and bad Bayesian use point estimates such as Bayes Factors, a good review is this is https://link.springer.com/article/10.3758/s13423-016-1221-4 2. But the leap from theta to probability of heads I think is an intuitive leap that happens to be correct but unjustified.   Philosophically then the posterior predictive is actually frequents, allow me to explain: Frequents are people who estimates a parameter and then draws fake samples from that point estimate and summarize it in confidence intervals, to justify this they imagine parallel worlds and what not. Bayesian are people who assumes a prior distributions from which the parameter is drawn, they thus have both prior and likelihood uncertainty which gives posterior uncertainty, which is the uncertainty of the parameters in their model, when a Bayesian wants to use his model to make predictions then they integrate their model parameters out and thus have a predictive distribution of new data given data*. Because this is a distribution of the data like the Frequentists sampling function, then we can actually draw from it multiple times to compute summary statistics much like the frequents, and calculate things such as a "Bayesian P-value" which describes how likely the model is to have generated our data, here the goal is for the p-value to be high because that suggests that the model describes the data well.   *In the real world they do not integrate out theta, they draw it 10.000 times and use thous samples as a stand in distribution because the math is to hard for complex models
2[anonymous]
Excellent! One final point that I would like to add is if we say that “theta is a physical quantity s.t. [...]“, we are faced with an ontological question: “does a physical quantity exist with these properties?”.    I recently found about Professor Jaynes’ A_p distribution idea, it is introduced in chapter 18 of his book, from Maxwell Peterson in the sub-thread below and I believe it is an elegant workaround to this problem. It leads to the same results but is more satisfying philosophically. This is how it would work in the coin flipping example: Define A(u) to a function that maps from real numbers to propositions with domain [0, 1] s.t.  1. The set of propositions {A(u): 0 <= u <= 1} is mutually exclusive and exhaustive  2. P(y=1 | A(u)) = u and P(y=0 | A(u)) = 1 - u Because the set of propositions is mutually exclusive and exhaustive, there is one u s.t.  A(u) is true and for any v != u, A(v) is false. We call this unique value of u: theta.    It follows that P(y=1 | theta) = theta and P(y=0 | theta) = 1 - theta and we use this to calculate the posterior predictive distribution 
[-][anonymous]10

Appreciate your reply. I think the source of my confusion is there being uncertainty in the degree of plausibility that we assign given our knowledge or there being uncertainty in our degree of belief given our knowledge. This feels a bit unnatural to me because this quantity is not an external/physical and unknown quantity but one that we assign given our knowledge. If we were to think of probabilities as physical properties that are unknown, then it makes sense to me that there can uncertainty in its value. How would you reconcile this?

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2Jan Christian Refsgaard
The probability is an external/physical thing because your brain is physical, but I take your point. I think the we/our distinction arises because we have different priors
2TAG
That's a very misleading way of looking at it.
2[anonymous]
These subjective Bayesians... :) I feel the same way about that statement. Could you please elaborate?
1Jan Christian Refsgaard
Uncertainty is a statement about my brain not the real world, if you replicate the initial conditions then it will always land either Head or Tails, so even if the coin is "fair" p(H∣θ)=0.5, then maybe  p(H∣θ,very good at physics)=0.95. the uncertainty comes form be being stupid and thus being unable to predict the next coin toss. Also there are two things we are uncertain about, we are uncertain about θ (the coins frequency) and we are uncertain about p(H∣θ), the next coin toss
1[anonymous]
So you are saying that “we” are uncertain about the degree of belief/plausibility that what our brain is going to assign? Then who are “we” exactly? Apologies for being glib but I really don’t understand  Also, it is a crime to have different priors given the same information according to us objective Bayesians so that can’t be the issue

Maxwell Peterson

30

Jaynes has a wonderful section in the same book where he discusses coin-flipping in depth. He flips a pickle jar lid in his kitchen in different ways to demonstrate how the method of flipping is critical - I love this whole section - and ends by saying that it’s a “problem of mechanics, highly complicated”. Section 10.3 (p317), How to cheat at coin and die tossing.

I’d thought he talked about this kind of “probability of a probability” kind of thing in the Chapter on the A_p distribution, and page 560 does have that phrase (though later on the page he says “The term ‘probability of a probability’ misses the point”…), but reading it again now it seems like I didn’t really understand this section. But give pages 560-563 a shot anyway.

[-][anonymous]10

Thank you so much for telling me about A_p distribution! This is exactly what I have been looking for.

“Pending a better understanding of what that means, let us adopt a cautious notation that will avoid giving possibly wrong impressions. We are not claiming that P(Ap|E) is a ‘real probability’ in the sense that we have been using that term; it is only a number which is to obey the mathematical rules of probability theory. Perhaps its proper conceptual meaning will be clearer after getting a little experience using it. So let us refrain from using the prefi... (read more)

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2Maxwell Peterson
I don't think so. Like you, I don't really understand this Ap stuff philisophically. But the step where you drop the prior P(Ap|I) to obtain P(Ap|D,I)∝P(D|Ap,I) is, I think, not warranted. Dropping the prior term outright like that... I don't think there are many cases where that's acceptable. Doing so does not reflect a state of low knowledge, but instead a state of pretty strong knowledge. To give intuition on what I mean: Contrast with the prior that reflects the state of knowledge "All I know is that H is possible and T is possible". This is closer to Jaynes' example about whether there's life on Mars. The prior that reflects that state of knowledge is Beta(1,1), which after two heads come up, becomes Beta(3, 1). The mean of Beta(3, 1) is 3/4 = 0.75. This is much less than the 1.0 you arrive at.  A prior that gives 1.0 after the data H,H might be something like: "This coin is very unfair in a well-known, specific way: It either always gives heads, always gives tails, or gives heads and tails alternating: 'H,T,H,T...'."  Under that prior, the data HH would give you a probability of near-1 that H is next. But that's a prior that reflects definite, strong knowledge of the coin. Maybe this argument changes given the nature of Ap, which again I don't really understand. But whatever it is, I don't think it's valid to assume the prior away.  
2Maxwell Peterson
Ah, wait, I misunderstood. You're interested in the mode, huh - that's why you're taking the argmax. In my Beta(3,1) example, the mode is also 1. So no problem there. I was focused on the mean in my previous comment. I still think dropping the prior is bad but now I'm not sure how to argue the point...  
1[anonymous]
I dropped the prior for two reason: 1. I assumed the background information to be indifferent to the A_p’s 2. We do not explicitly talk about the nature of the A_p’s. Prof. Jaynes defines it as a proposition such that P(A|A_p, E) = p. In my example A_p is defined as a proposition such that P(H|A_p, I) = p. No matter what prior information we have, it is going to be indifferent to the A_p’s by virtue of the fact that we don’t know what A_p represents Is this justification valid?
2Maxwell Peterson
Isn’t A_p the distribution over how often the coin will come up heads, or the probability of life on Mars? If so… there’s no way those things could be indifferent to the background information. A core tenet of the philosophy outlined in this book is that when you ignore prior information without good cause, things get wacky and fall apart. This is part of desiderata iii from chapter 2: “The robot always takes into account all of the evidence it has relevant to a question. It does not arbitrarily ignore some of the information, basing its conclusions only on what remains.” (Then Jaynes ignores information in later chapters because it doesn’t change the result… so this desideratum is easier said than done… but yeah)
1[anonymous]
“[…] A_p the distribution over how often the coin will come up heads […]” - I understood A_p to be a sort of distribution over models; we do not know/talk about the model itself but we know that if a model A_p is true, then the probability of heads is equal to p by definition of A_p. Perhaps the model A_p is the proposition “the centre of mass of the coin is at p” or “the bias-weighting of the coin is p” but we do not care as long the resulting probability of heads is p. So how can the prior not be indifferent when we do not know the nature of each proposition A_p in a set of mutually exclusive and exhaustive propositions?
2Maxwell Peterson
I can’t see anything wrong in what you’ve said there, but I still have to insist without good argument that dropping P(A_p|I) is incorrect. In my vague defense, consider the two A_p distributions drawn on p558, for the penny and for Mars. Those distributions are as different as they are because of the different prior information. If it was correct to drop the prior term a priori, I think those distributions would look the same?
1[anonymous]
You are right; dropping priors in the A_p distribution is probably not a general rule. Perhaps the propositions don’t always need to interpretable for us to be able impose priors? For example, people impose priors over the parameter space of a neural network which is certainly not interpretable. But the topic of Bayesian neural networks is beyond me
2Maxwell Peterson
It seems like in practice, when there’s a lot of data, people like Jaynes and Gelman are happy to assign low-information (or “uninformative”) priors, knowing that with a lot of data the prior ends up getting washed away anyway. So just slapping a uniform prior down might be OK in a lot of real-world situations. This is I think pretty different than just dropping the prior completely, but gets the same job done.
2Maxwell Peterson
Now I’m doubting myself >_> is it pretty different?? Anyone lurking reading this who knows whether uniform prior is very different than just dropping the prior term?
1[anonymous]
I believe it is the same thing. A uniform prior means your prior is constant function i.e. P(A_p|I) = x where x is a real number with the usual caveats. So if you have a uniform prior, you can drop it (from a safe height of course). But perhaps the more seasoned Bayesians disagree? (where are they when you need them)
2Maxwell Peterson
Shoot! You’re right! I think I was wrong this whole time on the impact of dropping the prior term. Cuz data term * prior term is like multiplying the distributions, and dropping the prior term is like multiplying the data distribution by the uniform one. Thanks for sticking with me :)
1[anonymous]
No worries :) Thanks a lot for your help! Much appreciated.  It’s amazing how complex a simple coin flipping problem can get when we approach it from our paradigm of objective Bayesianism. Professor Jaynes remarks on this after deriving the principle of indifference: “At this point, depending on your personality and background in this subject, you will be either greatly impressed or greatly disappointed by the result (2.91).” - page 40 A frequentist would have “solved“ this problem rather easily. Personally, I would trade simplicity for coherence any day of the week...
2Maxwell Peterson
I looooove that coin flip section! Cheers
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