Decision theory is not one of my strengths, and I have a question about it.
Is there a consensus view on how to deal with the problem of "rival formalizations"? Peterson (2009) illustrates the problem like this:
Imagine that you are a paparazzi photographer and that rumour has it that actress Julia Roberts will show up in either New York (NY), Los Angeles (LA) or Paris (P). Nothing is known about the probability of these states of the world. You have to decide if you should stay in America or catch a plane to Paris. If you stay and [she] shows up in Paris you get $0; otherwise you get your photos, which you will be able to sell for $10,000. If you catch a plane to Paris and Julia Roberts shows up in Paris your net gain after having paid for the ticket is $5,000, and if she shows up in America you for some reason, never mind why, get $6,000. Your initial representation of the decision problem is visualized in Table 2.13.
Table 2.13
P | LA | NY | |
Stay | $0 | $10k | $10k |
Go to Paris | $5k | $6k | $6k |
Since nothing is known about the probabilities of the states in Table 2.13, you decide it makes sense to regard them as equally probable [see Table 2.14].
Table 2.14
P (1/3) | LA (1/3) | NY (1/3) | |
Stay | $0 | $10k | $10k |
Go to Paris | $5k | $6k | $6k |
The rightmost columns are exactly parallel. Therefore, they can be merged into a single (disjuntive) column, by adding the probabilities of the two rightmost columns together (Table 2.15).
Table 2.15
P (1/3) | LA or NY (2/3) | |
Stay | $0 | $10k |
Go to Paris | $5k | $6k |
However, now suppose that you instead start with Table 2.13 and first merge the two repetitious states into a single state. You would then obtain the decision matrix in Table 2.16.
Table 2.16
P | LA or NY | |
Stay | $0 | $10k |
Go to Paris | $5k | $6k |
Now, since you know nothing about the probabilities of the two states, you decide to regard them as equally probable... This yields the formal representation in Table 2.17, which is clearly different from the one suggested above in Table 2.15.
Table 2.17
P (1/2) | LA or NY (1/2) | |
Stay | $0 | $10k |
Go to Paris | $5k | $6k |
Which formalisation is best, 2.15 or 2.17? It seems question begging to claim that one of them must be better than the other — so perhaps they are equally reasonable? If they are, we have an example of rival formalisations.
Note that the principle of maximising expected value recommends different acts in the two matrices. According to Table 2.15 you should stay, but 2.17 suggests you should go to Paris.
Does anyone know how to solve this problem? If one is not convinced by the illustration above, Peterson (2009) offers a proof that rival representations are possible on pages 33–35.
As far as I can tell, this is just the standard complaint about the (naive?) Principle of Indifference and doesn't have much to do with decision theory per se. E.g., here's Keynes talking about a similar case. The most plausible solutions I know of are to either 1. insist that there simply are no rational constraints besides the axioms of probability on how we should weight the various possibilities in the absence of evidence and hence the problem is underdetermined (it depends on our "arbitrary" priors), or 2. accept that this is a real problem with Bayesian epistemology and hope something better comes along that doesn't model all doxastic attitudes as probabilities.
Or, I suppose, 3. Tells us how to actually calculate some priors. That would be fine too.