You got a 50% chance.
No, you don't. Switching gives you the right door 2 out of 3 times. Long before reading this article, I was convinced by a program somebody wrote that actually simulates it by counting up how many times you would win or lose in that situation... and it comes out that you win by switching, 2 out of 3 times.
So, the interesting question at that point is, why does it work 2 out of 3 times?
And so now, you have an opportunity to learn another reason why your intuition about probabilities is wrong. It's not just the lack of "memory" that makes probabilities weird. ;-)
Think about it this way. Let's say you precommit before we play Monty's game that you won't switch. Then you win 1/3rd of the time, exactly when you picked the correct door first, yes?
Now, suppose you precommit to switching. Under what circumstances will you win? You'll win if you didn't pick the correct door to start with. That means you have a 2/3rd chance of winning since you win whenever your first door wasn't the correct choice.
Your comparison to the roulette wheel doesn't work: The roulette wheel has no memory, but in this case, the car isn't reallocated between the two remaining doors, it was chosen before the process started.