If you wager your entire bankroll every time you place a bet, your bankroll will eventually be 0.
Expected Value
Expected value is the average amount we receive if we repeat a bet an infinite number of times.
E[X]=∑ixiP(xi)
Where:
xi - the percentage of stake won or lost from outcome $i$
P(xi) - the probability of that outcome.
For a typical sports bet, $x_i$ can be found with the equation:
xi=S(Oi−1)B0
Where:
S - stake
Oi - decimal odds of outcome $i$
B0 - initial bankroll before bet
This calculates the relative increase in our bankroll from each possible outcome. For a losing scenario, xi=−SB0 as we just lose our stake.
Using EV
This can be used as a performance metric for a bet – if one bet has an expected value of 5% and another 10% we would tend to prefer the latter to the former. However, this ignores relative likelihoods on the different outcomes.
E.g. If a bet has a 0.0000001% likelihood but pays out 11,000,000% the expected value is 10%, but this is not an attractive bet for most people. You certainly wouldn't expect a 10% return on your investment.
So we need a system dependent on the player's current bankroll.
Enter Expected Growth
The fundamental issue is that, while expected value calculates the long-term value of infinitely repeating a bet, in any real scenario we can only bet once, and only get one outcome.
This is the problem with the previous example, as despite being positive EV, you could only bet fractions of a penny if you have any hope to be paid out before your bankroll hits 0. So while you have an expected value of 10%, the _expected outcome_ is that you lose the wager almost every time.
We can formalize this:
EG[X]=−1+∏i(1+xi)P(xi)
xi is the money won/lost relative to your entire bankroll, as opposed to expected value, which is relative to your stake.
This is expected growth, and it uses the expected outcomes of an event rather than the value. For any given case, expected growth will be less than the expected value. This lends itself to the idea of a finite bankroll, so that no matter how positive EV a bet is, betting too much can cause your bankroll to shrink.
If you wager your entire bankroll every time you place a bet, your bankroll will eventually be 0.
Let us take this as an example for EG, any outcome that causes you to lose your entire bankroll (xi=−1) will imply EG=−1, no matter the probability of that event occurring. This is because if something is possible, it will happen eventually and stop the entire system.
Applying the concept to a sports bet, we can calculate the expected bankroll after a single bet:
Expected Value
E[X]=∑ixiP(xi)Where:
For a typical sports bet, $x_i$ can be found with the equation:
xi=S(Oi−1)B0Where:
This calculates the relative increase in our bankroll from each possible outcome. For a losing scenario, xi=−SB0 as we just lose our stake.
Using EV
This can be used as a performance metric for a bet – if one bet has an expected value of 5% and another 10% we would tend to prefer the latter to the former. However, this ignores relative likelihoods on the different outcomes.
So we need a system dependent on the player's current bankroll.
Enter Expected Growth
The fundamental issue is that, while expected value calculates the long-term value of infinitely repeating a bet, in any real scenario we can only bet once, and only get one outcome.
This is the problem with the previous example, as despite being positive EV, you could only bet fractions of a penny if you have any hope to be paid out before your bankroll hits 0. So while you have an expected value of 10%, the _expected outcome_ is that you lose the wager almost every time.
We can formalize this:
EG[X]=−1+∏i(1+xi)P(xi)value, which is relative to your stake.
This is expected growth, and it uses the expected outcomes of an event rather than the
value. For any given case, expected growth will be less than the expected value. This
lends itself to the idea of a finite bankroll, so that no matter how positive EV a bet
is, betting too much can cause your bankroll to shrink.
Let us take this as an example for EG, any outcome that causes you to lose your entire bankroll (xi=−1) will imply EG=−1, no matter the probability of that event occurring. This is because if something is possible, it will happen eventually and stop the entire system.
Applying the concept to a sports bet, we can calculate the expected bankroll after a single bet:
B∗=B0×∏i(1+S(Oi−1)B0)P(xi)