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"20% a bear would scratch my tent : 50% a notbear would"

I think the chance that your tent gets scratched should be strictly higher if there's a bear around?

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1Zane1y

You can just try to estimate the base rate of a bear attacking your tent and eating you, then estimate the base rate of a thing that looks identical to a bear attacking your tent and eating you, and compare them. Maybe one in a thousand tents get attacked by a bear, and 1% of those tent attacks end with the bear eating the person inside. The second probability is a lot harder to estimate, since it mostly involves off-model surprises like "Bigfoot is real" and "there is a serial killer in these woods wearing a bear suit," but I'd have trouble seeing how it could be above one in a billion. (Unless we're including possibilities like "this whole thing is just a dream" - which actually should be your main hypothesis.) In general, when you're dealing with very low or very high probabilities, I'd recommend you just try to use your intuition instead of trying to calculate everything out explicitly.* The main reason is this: if you estimate a probability as being 30% instead of 50%, it won't usually affect the result of the calculation that much. On the other hand, if you estimate a probability as being 1/10^5 instead of 1/10^6, it can have an enormous impact on the end result. However, humans are a lot better at intuitively telling apart 30% from 50% than they are at telling apart 1/10^5 from 1/10^6. If you try to do explicit calculations about probabilities that are pretty close to 1:1, you'll probably get a pretty accurate result; if you try to do explicit calculations about probabilities that are several orders of magnitude away from each other, you'll probably be off by at least one order of magnitude. In this case, you calculated that even if a person on a camping trip is being eaten by something that looks identical to a bear, there's still about a 2.6% chance that it's not a bear. When you get a result that ridiculous, it doesn't mean there's a nonbear eating you, it means you're doing the math wrong. *The situations in which you can get useful information f

3Screwtape1y

I'm not sure I'm following your actual objection. Is your point that this algorithm is wrong and won't update towards the right probabilities even if you keep feeding it new pieces of evidence, that the explanations and numbers for these pieces of evidence don't make sense for the implied story, that you shouldn't try to do explicit probability calculations this way, or some fourth thing? If this algorithm isn't actually equivalent to Bayes in some way, that would be really useful for someone to point out. At first glance it seems like a simpler (to me anyway) way to express how making updates works, not just on an intuitive "I guess the numbers move that direction?" way but in a way that might not get fooled by e.g. the mammogram example. If these explanations and numbers don't make exact sense for the implied story, that seems fine? "A train is moving from east to west at a uniform speed of 12 m/s, ten kilometers west a second train is moving west to east at a uniform speed of 15 m/s, how far will the first train have traveled when they meet?" is a fine word problem even if that's oversimplified for how trains work. If you don't think it's worth doing explicit probability calculations this way, even to practice and try and get better or as a way to train the habit of how the numbers should move, that seems like a different objection and one you would have with any guide to Bayes. That's not to say you shouldn't raise the objection, but that doesn't seem like an objection that someone did the math wrong! And of course maybe I'm completely missing your point.

Zane1y122

Multiple points, really. I believe that this calculation is flawed in specific ways, but I also think that most calculations that attempt to estimate the relative odds of two events that were both very unlikely a priori will end up being off by a large amount. These two points are not entirely unrelated.

The specific problems that I noticed were:

The probabilities are not independent of each other, so they cannot be multiplied together directly. A bear flipping over your tent would almost always immediately be preceded by the bear scratching your tent, so up

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52 shortest goddamn bayes guide ever

by lemonhope

10th May 2024

1 min read

52

// ODDS = YEP:NOPE
YEP, NOPE = MAKE UP SOME INITIAL ODDS WHO CARES
FOR EACH E IN EVIDENCE
	YEP *= CHANCE OF E IF YEP
	NOPE *= CHANCE OF E IF NOPE

The thing to remember is that yeps and nopes never cross. The colon is a thick & rubbery barrier. Yep with yep and nope with nope.

bear : notbear =
1:100 odds to encounter a bear on a camping trip around here in general
* 20% a bear would scratch my tent : 50% a notbear would
* 10% a bear would flip my tent over : 1% a notbear would
* 95% a bear would look exactly like a fucking bear inside my tent : 1% a notbear would
* 0.01% chance a bear would eat me alive : 0.001% chance a notbear would

As you die you conclude 1*20*10*95*.01 : 100*50*1*1*.001 = 190 : 5 odds that a bear is eating you.

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shortest goddamn bayes guide ever

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[-]Zane1y43

"20% a bear would scratch my tent : 50% a notbear would"

I think the chance that your tent gets scratched should be strictly higher if there's a bear around?

[-]lemonhope1y10

A possom or whatever will scratch mine like half the time

[-]Zane1y104

It doesn't matter how often the possum would have scratched it. If your tent would be scratched 50% of the time in the absence of a bear, and a bear would scratch it 20% of the time, then the chance it gets scratched if there is a bear is 1-(1-50%)(1-20%), or 60%. Unless you're postulating that bears always scare off anything else that might scratch the tent.

Also, what about how some of these probabilities are entangled with each other? Your tent being flipped over will almost always involve your tent being scratched, so once we condition on the tent being flipped over, that screens off the evidence from the tent being scratched.

Also, only 95% chance a bear would look like a bear? And only 0.01% chance it would eat you?

Realistically, once we've seen a bear-shaped object scratch your tent, flip it over, and start eating you, you should be way more confident than 38 to 1 that you're being eaten.

[-]lemonhope1y50

I was thinking the bear would scare other stuff off yeah. But now I think I'm doing this wrong and the code is broken. Can you fix my code?

[-]Zane1y10

In general, when you're dealing with very low or very high probabilities, I'd recommend you just try to use your intuition instead of trying to calculate everything out explicitly.* The main reason is this: if you estimate a probability as being 30% instead of 50%, it won't usually affect the result of the calculation that much. On the other hand, if you estimate a probability as being 1/10^5 instead of 1/10^6, it can have an enormous impact on the end result. However, humans are a lot better at intuitively telling apart 30% from 50% than they are at telling apart 1/10^5 from 1/10^6.

If you try to do explicit calculations about probabilities that are pretty close to 1:1, you'll probably get a pretty accurate result; if you try to do explicit calculations about probabilities that are several orders of magnitude away from each other, you'll probably be off by at least one order of magnitude. In this case, you calculated that even if a person on a camping trip is being eaten by something that looks identical to a bear, there's still about a 2.6% chance that it's not a bear. When you get a result that ridiculous, it doesn't mean there's a nonbear eating you, it means you're doing the math wrong.

*The situations in which you can get useful information from an explicit calculation on low probabilities are situations where you're fine with being off by substantial multiplicative factors. Like, if you're making a business decision where you're only willing to accept a <5% chance of something happening, and you calculate that there's only a one in a trillion chance, then it doesn't actually matter whether you were off by a factor of a million to one. (Of course, you still do need to check that there's no way you could be off by an even larger factor than that.)

[-]Screwtape1y31

If this algorithm isn't actually equivalent to Bayes in some way, that would be really useful for someone to point out. At first glance it seems like a simpler (to me anyway) way to express how making updates works, not just on an intuitive "I guess the numbers move that direction?" way but in a way that might not get fooled by e.g. the mammogram example.

If these explanations and numbers don't make exact sense for the implied story, that seems fine? "A train is moving from east to west at a uniform speed of 12 m/s, ten kilometers west a second train is moving west to east at a uniform speed of 15 m/s, how far will the first train have traveled when they meet?" is a fine word problem even if that's oversimplified for how trains work.

If you don't think it's worth doing explicit probability calculations this way, even to practice and try and get better or as a way to train the habit of how the numbers should move, that seems like a different objection and one you would have with any guide to Bayes. That's not to say you shouldn't raise the objection, but that doesn't seem like an objection that someone did the math wrong!

And of course maybe I'm completely missing your point.

[-]Zane1y122

The specific problems that I noticed were:

The probabilities are not independent of each other, so they cannot be multiplied together directly. A bear flipping over your tent would almost always immediately be preceded by the bear scratching your tent, so updating on both events would just be double-counting evidence.
The probabilities do not appear to be conditional probabilities. P(A&B&C&D) doesn't equal P(A)*P(B)*P(C)*P(D), it equals P(A)*P(B|A)*P(C|A&B)*P(D|A&B&C).
The "nonbear" hypothesis is lumping together several different hypotheses. P(A|notbear) & P(B|notbear) cannot be multiplied together to get P(A&B|notbear), because (among other reasons) there may be some types of notbears that are very likely to do A but very unlikely to do B, some that are very likely to do both, and so on. Once you've observed A, it should update you on what kind of notbear it could be, and thus change the probability it does B.
The "20% a bear would scratch my tent : 50% a notbear would" claim is incorrect for the reasons I mentioned above. If your tent would be scratched 50% of the time in the absence of a bear, and a bear would scratch it 20% of the time, then the chance it gets scratched if there is a bear is 1-(1-50%)(1-20%), or 60%. (Unless you're postulating that bears always scare off anything else that might scratch the tent - which it seems Luke is indeed claiming.)
I disagree with several of the specific claims about the probabilities, such as "95% chance a bear would look exactly like a fucking bear inside my tent" and "1% chance a notbear would."

And then the meta-problem: when you're multiplying together more than two or three probabilities that you estimated, particularly small ones, errors in your ability to estimate them start to add up. Which is why I don't think it's usually worthwhile to try and estimate probabilities like this.

But you have a fair point about it being a good idea to practice explicit calculations, even if they're too complicated to reliably get right in real life. So here's how I might calculate it:

P(bear encounters you): 1%.

P(tent scratched | bear): 60%, for the reasons I said above... unless we take into account it scaring away other tent-scratching animals, in which case maybe 40%.

P(tent flipped over | bear & tent scratched): 20%, maybe? I think if the bear has already taken an interest in your tent, it's more likely than usual to flip it over.

P(you see a bear-shaped object | bear & tent scratched & tent flipped over): Bears always look like bears. This is so close to 100% I wouldn't even normally include it in the calculation, but let's call it 99.99%.

P(you get eaten | bear & tent scratched & tent flipped over & you see a bear-shaped object): It's already pretty been aggressive so far, so I'd say perhaps 5%.

On the other side, there are almost no objects for which the probability of it looking exactly like a bear isn't infinitesimal; let's only consider Bigfoot and serial-killer-who's-a-furry for simplicity, then add them up.

P(Bigfoot exists): ...hmm. I am not an expert on the matter, but let's say 1%.

P(Bigfoot encounters you | Bigfoot exists): There can't be that many Bigfoots (Bigfeet?) out there, or else people would have caught one. 0.01%.

P(tent scratched | Bigfoot): Bigfeet are probably more aggressive than bears, so 70%.

P(tent flipped over | Bigfoot): Again, Bigfeet are supposed to be pretty aggressive, so 50%.

P(you see a bear-shaped object | Bigfoot & tent scratched & tent flipped over): Bigfoot looks similar enough to a bear that you'll almost certainly think he's a bear. 99%.

P(you get eaten | Bigfoot & tent scratched & tent flipped over & you see a bear-shaped object): Again, Bigfeet aggressive, 30%.

Then for the furry cannibal one:

P(furry cannibal stalking this forest): 0.000001% (that's one in a hundred million, if I got my zeroes right). I welcome you to prove me wrong on the matter by manually increasing the number of furry cannibals in a given forest.

P(furry cannibal encounters you | furry cannibal exists): How large of a forest is this? Well, he probably has his methods of locating prey, so let's say 10%. Wait, why did I assume he's a "he"? What gender is the typical furry cannibal? Probably a trans woman? Let's name this furry cannibal Susan.

P(tent scratched | Susan): Probably not that high; she doesn't want to wake you up too soon. 30%.

P(tent flipped over | Susan & tent scratched): She might just sneak in, but let's say 90%.

P(you see a bear-shaped object | Susan & tent scratched & tent flipped over): She's wearing a bear costume, as hypothesized; 99.99%.

P(you get eaten | Susan & tent scratched & tent flipped over & you see a bear-shaped object): Yes, of course this happens; this was her whole kink in the first place! 99%.

So for "bear," we have 1%*40%*20%*99.99%*5% = 0.004%. For "Bigfoot," we have 1%*0.01%*70%*50%*99%*30% = 0.00001%. For "Susan," we have 0.000001%*10%*30%*90%*99.99%*99% = .000000027%. Looks like Bigfoot was so much more likely than Susan that we can pretty much just forget the Susan possibility altogether. It's 0.004 to 0.00001, so 400 to 1 chance that you're being eaten by a bear.

(Although I actually think you should be even more confident than 400 to 1 that it's a bear rather than Bigfoot, and that I just was off by an order of magnitude for one reason or another, as happens when you're doing these sorts of calculations. And if you ever actually observe all of these things, the most likely hypothesis is that you're dreaming.)

[-]keltan1y20

In my head I was thinking a tree branch moving in the wind.

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