All of Incorrect's Comments + Replies

My visualization ability improves the closer I am to sleep, being near perfect during a lucid dream.

You can generally throw unfalsifiable beliefs into your utility function but you might consider this intellectually dishonest.

As a quick analogy, a solipsist can still care about other people.

I escape by writing a program that simulates 3^^3 copies of myself escaping and living happily ever after (generating myself by running Solomonoff Induction on a large amount of text I type directly into the source code).

I'm guessing Eliezer would lose most of his advantages against a demographic like that.

Yeah, they'd both lack background knowledge to RP the conversation and would also, I presume, be much less willing to lose the money than if they'd ventured the bet themselves. Higher-stakes games are hard enough already (I was 1 for 3 on those when I called a halt). And if it did work against that demographic with unsolicited requests (which would surprise me) then there would be, cough, certain ethical issues.

Oh god, remind me to never play the part of the gatekeeper… This is terrifying.

0wedrifid
Why is it that the role of gatekeeper terrifies you? I'm curious. The role of the AI sounds mildly abhorrent to me but being the gatekeeper seems relaxing. It isn't that hard to say "No, and after talking to you for the allotted time is up I'm going to raze your entire building with thermite." (Mind you, the prospect of playing gatekeeper against an actual AI and for some reason not being able to destroy it instantly does sound terrifying! But humans are different.)

The lifespan dilemma applies to all unbounded utility functions combined with expected value maximization, it does not require simple utilitarianism.

Would your post on eating babies count, or is it too nonspecific?

http://lesswrong.com/lw/1ww/undiscriminating_skepticism/1scb?context=1

(I completely agree with the policy, I'm just curious)

7quiet
We should exempt any imagery fitting of a Slayer album cover, lest we upset the gods of metal with our weakness.

There are people who claim to be less confused about this than I am

Solipsists should be able to dissolve the whole thing easily.

Thanks, can you recommend a textbook for this stuff? I've mostly been learning off Wikipedia.

I can't find a textbook on logic in the lesswrong textbook list.

1elseif
I'm a fan of Enderton's "A Mathematical Introduction to Logic". It's short and very precisely written, which can make it a little difficult to learn from on its own, but together with a general familiarity with the subject and using wikipedia for additional examples elaboration, it should be perfect.

Therefore a theory could be ω-consistent because it fails to prove P(n), even though P(n) is true in the standard model.

I thought for ω-consistency to even be defined for a theory it must interpret the language of arithmetic?

0elseif
Perhaps LessWrong is a place where I can say "Your question is wrong" without causing unintended offense. (And none is intended.) Yes, for ω-consistency to even be defined for a theory it must interpret the language of arithmetic. This is a necessary precondition for the statement you quoted, and does not contradict it. Work in PA, and take a family of statements P(n) where each P(n) is true but independent of PA, and not overly simple statements themselves---say, P(n) is "the function epsilon n in the fast growing hierarchy is a total function". (The important thing here is that the statement is at least Pi2---true pure existence statements are always provable, and if the statements were universal there would be a different ω-consistency problem. The exact statement isn't so important, but not that these statements are true, but not provable in PA.) Now consider the statement T="there is an n such that P(n) is false". PA+T has no standard model (because T is false), but PA+T doesn't prove any of the P(n), let alone all of them, so there's no ω-consistency problem.

Just use the axiom schema of induction instead of the second order axiom of induction and you will be able to produce theorems though.

But you wont be able to produce all true statements in SOL PA, that is, PA with the standard model, because of the incompleteness theorems. To be able to prove a larger subset of such statements, you would have to add new axioms to PA. If adding an axiom T to PA does not prevent the standard model from being a model of PA+T, that is it does not prove any statements that require the existence of nonstandard numbers, then P... (read more)

0elseif
ω-inconsistency isn't exactly the same thing as being false in the standard model. Being ω-inconsistent requires both that the theory prove all the statements P(n) for standard natural numbers n, but also prove that there is an n for which P(n) fails. Therefore a theory could be ω-consistent because it fails to prove P(n), even though P(n) is true in the standard model. So even if we could check ω-consistency, we could take PA, add an axiom T, and end up with an ω-consistent theory which nonetheless is not true in the standard model. By the way, there are some papers on models for adding random (true) axioms to PA. "Are Random Axioms Useful?" involves some fairly specific cases, but shows that in those situations, random axioms generally aren't likely to tell you anything you wanted to know.

There's no complete deductive system for second-order logic.

An infinite number of axioms like in an axiom schema doesn't really hurt anything, but you can't have infinitely long single axioms.

∀x((x = 0) ∨ (x = S0) ∨ (x = SS0) ∨ (x = SSS0) ∨ ...)

is not an option. And neither is the axiom set

P0(x) iff x = 0
PS0(x) iff x = S0
PSS0(x) iff x = SS0
...
∀x(P0(x) ∨ PS0(x) ∨ PS0(x) ∨ PS0(x) ∨ ...)

We could instead try the axioms

P(0, x) iff x = 0
P(S0, x) iff x = S0
P(SS0, x) iff x = SS0
...
∀x(∃n(P(n, x)))

but then again we have the problem of n being a nonstandard number.

I don't see what the difference is... They look very similar to me.

At some point you have to translate it into a (possibly infinite) set of first-order axioms or you wont be able to perform first-order resolution anyway.

-2Eugine_Nier
What's wrong with second order resolution?

I don't see how you would define Pn(x) in the language of PA.

Let's say we used something like this:

Pn(x) iff ((0 + n) = x)

Let's look at the definition of +, a function symbol that our model is allowed to define:

a + 0 = a
a + S(b) = S(a + b)

"x + 0 = x" should work perfectly fine for nonstandard numbers.

So going back to P(x):

"there exists some n such that ((0 + n) = x)"

for a nonstandard number x, does there exist some number n such that ((0+n) = x)? Yup, the nonstandard number x! Set n=x.

Oh, but when you said nth successor you meant n had to be standard? Well, that's the whole problem isn't it!

1TorqueDrifter
But any nonstandard number is not an nth successor of 0 for any n, even nonstandard n (whatever that would mean). So your rephrasing doesn't mean the same thing, intuitively - P is, intuitively, "x is reachable from 0 using the successor function". Couldn't you say: * P0: x = 0 * PS0: x = S0 * PSS0: x = SS0 and so on, defining a set of properties (we can construct these inductively, and so there is no Pn for nonstandard n), and say P(x) is "x satisfies one such property"?

Are you saying that in reality every property P has actually three outcomes: true, false, undecidable?

By Godel's incompleteness theorem yes, unless your theory of arithmetic has a non-recursively enumerable set of axioms or is inconsistent.

And that those always decidable, like e.g. "P(n) <-> (n = 2)" cannot be true for all natural numbers, while those which can be true for all natural numbers, but mostly false otherwise, are always undecidable for... some other values?

I'm having trouble understanding this sentence but I think I know ... (read more)

Could someone please confirm my statements in the new sequence post about first-order logic? I want to be sure my understanding is correct.

http://lesswrong.com/lw/f4e/logical_pinpointing/7qv6?context=1#7qv6

0cousin_it
Eugine_Nier's response seems right to me, and this paragraph on Wikipedia might be relevant...

If our axiom set T is independent of a property P about numbers then by definition there is nothing inconsistent about the theory T1 = "T and P" and also nothing inconsistent about the theory T2= "T and not P".

To say that they are not inconsistent is to say that they are satisfiable, that they have possible models. As T1 and T2 are inconsistent with each other, their models are different.

The single zero-based chain of numbers without nonstandard numbers is a single model. Therefore, if there exists a property about numbers that is indep... (read more)

"Because if you had another separated chain, you could have a property P that was true all along the 0-chain, but false along the separated chain. And then P would be true of 0, true of the successor of any number of which it was true, and not true of all numbers."

But the axiom schema of induction does not completely exclude nonstandard numbers. Sure if I prove some property P for P(0) and for all n, P(n) => P(n+1) then for all n, P(n); then I have excluded the possibility of some nonstandard number "n" for which not P(n) but ther... (read more)

-2Houshalter
For any number n, n-n=0. If you have a separate chain that isn't connected to zero, then this isn't true. However this statement is pretty simple and can be expressed in first order logic. I have no idea why EY believes that it requires second order logic to eliminate the possibility of other chains that aren't derived from zero.
0Eugine_Nier
Eliezer isn't using an axiom schema, he's using an axiom of second order logic.
1TorqueDrifter
Pn(x) is "x is the nth successor of 0" (the 0th successor of a number is itself). P(x) is "there exists some n such that Pn(x)".
1Viliam_Bur
Not sure if I understand the point of your argument. Are you saying that in reality every property P has actually three outcomes: true, false, undecidable? And that those always decidable, like e.g. "P(n) <-> (n = 2)" cannot be true for all natural numbers, while those which can be true for all natural numbers, but mostly false otherwise, are always undecidable for... some other values? I don't know. Let's suppose that for any specific value V in the separated chain it is possible to make such property PV. For example "PV(x) <-> (x <> V)". And let's suppose that it is not possible to make one such property for all values in all separated chains, except by saying something like "P(x) <-> there is no such PV which would be true for all numbers in the first chain and false for x". What would that prove? Would it contradict the article? How specifically?
1Incorrect
If our axiom set T is independent of a property P about numbers then by definition there is nothing inconsistent about the theory T1 = "T and P" and also nothing inconsistent about the theory T2= "T and not P". To say that they are not inconsistent is to say that they are satisfiable, that they have possible models. As T1 and T2 are inconsistent with each other, their models are different. The single zero-based chain of numbers without nonstandard numbers is a single model. Therefore, if there exists a property about numbers that is independent of any theory of arithmetic, that theory of arithmetic does not logically exclude the possibility of nonstandard elements. By Godel's incompleteness theorems, a theory must have statements that are independent from it unless it is either inconsistent or has a non-recursively-enumerable theorem set. Each instance of the axiom schema of induction can be constructed from a property. The set of properties is recursively enumerable, therefore the set of instances of the axiom schema of induction is recursively enumerable. Every theorem of Peano Arithmetic must use a finite number of axioms in its proof. We can enumerate the theorems of Peano Arithmetic by adding increasingly larger subsets of the infinite set of instances of the axiom schema of induction to our axiom set. Since the theory of Peano Arithmetic has a recursively enumerable set of theorems it is either inconsistent or is independent of some property and thus allows for the existence of nonstandard elements.

Oh don't worry, there will always be those little lapses in awareness. Even supposing you hide yourself at night, are you sure you maintain your sentience while awake? Ever closed your eyes and relaxed, felt the cool breeze, and for a moment, forgot you were aware of being aware of yourself?

Are you saying that dying after a billion years sounds sad to you?

And therefore you would have a thousand-year-old brain that can make trillion-year plans.

0MugaSofer
Seems legit.

I think I have a better understanding now.

For every statement S and for every action A, except the A Myself() actually returns, PA will contain a theorem of the form (Myself()=A) => S because falsehood implies anything. Unless Myself() doesn't halt, in which case the value of Myself() can be undecidable in PA and Myself's theorem prover wont find anything, consistent with the fact that Myself() doesn't halt.

I will assume Myself() is also filtering theorems by making sure Universe() has some minimum utility in the consequent.

If Myself() halts, then if th... (read more)

How does ambient decision theory work with PA which has a single standard model?

It looks for statements of the form Myself()=C => Universe()=U

(Myself()=C), and (Universe()=U) should each have no free variables. This means that within a single model, their values should be constant. Thus such statements of implication establish no relationship between your action and the universe's utility, it is simply a boolean function of those two constant values.

What am I missing?

2Vladimir_Nesov
The problem is that the agent doesn't know what Myself() evaluates to, so it's not capable of finding an explicitly specified function whose domain is a one-point set with single element Myself() and whose value on that element is Universe(). This function exists, but the agent can't construct it in an explicit enough form to use in decision-making. Let's work with the graph of this function, which can be seen as a subset of NxN and includes a single point (Myself(), Universe()). Instead, the agent works with an extension of that function to the domain that includes all possible actions, and not just the actual one. The graph of this extension includes a point (A, U) for each statement of the form [Myself()=C => Universe()=U] that the agent managed to prove, where A and U are explicit constants. This graph, if collected for all possible actions, is guaranteed to contain the impossible-to-locate point (Myself(), Universe()), but also contains other points. The bigger graph can then be used as a tool for the study of the elusive (Myself(), Universe()), as the graph is in a known relationship with that point, and unlike that point it's available in a sufficiently explicit form (so you can take its argmax and actually act on it). (Finding other methods of studying (Myself(), Universe()) seems to be an important problem.)

15: discover ordinal hierarchy of Tegmark universes, discover method of constructing the set of all ordinals without contradiction, create level n Tegmark universe for all n

It was supposed to be a sarcastic response about being too strict with definitions but obviously didn't end up being funny.

I am not a Will Newsome sockpuppet. I'll refrain from making the lower quality subset of my comments henceforth.

The parent is bad, but someone banned it (I unbanned it for now), and I'm not aware of a policy that permits banning in such cases. Please clarify.

0[anonymous]
Convince me this isn't an attempt to obfuscate the discussion with unnecessarily legalistic definitions. Otherwise I'm chalking it up to logical rudeness.
-2[anonymous]
I'm guessing the "human" bit was to make sure Clippy (sorry, "User:"Clippy) doesn't get control of the process :-P
3khafra
But surely you agree that tricking people into saying "I think Will is Incorrect" is exactly the sort of thing that would amuse him?
8ArisKatsaris
By that same argument murder is cute, rape is cute, arson is cute, genocide is cute -- and you prefer to live in a world where people call these things cute than in a world where they call them non-cute. You're using the word "cute" wrongly.

Example 54084954 of that fact that true-seeking and politeness are not correlated.

Also, a little fallacy of gray. Someone could be zero on the cute/disgusting scale, if even if it were so awful to label them disgusting.

5wedrifid
There is a difference between rejecting a "Will is a cute troll" meme being used to justify sock-puppet bait-and-switch abuse---by specifically referring to the behavior being not-cute---and simply saying that someone is not cute apropos of nothing. Your equivocation is either disingenuous or just silly.

He's really wondering whether the voxel-space is a directed graph or whether up∘down=down∘up=identity (and for left/right too). Movement could be commutative with up∘down≠identity.

Consider

voxels = {a, b}

left(a)  = a
right(a) = a
up(a)    = a
down(a)  = a

left(b)  = a
right(b) = a
up(b)    = a
down(b)  = a

If f is in (left, right, up, down)
let g be the respective function in (right, left, down, up)
forall x in {a, b}
f(g(x))=g(f(x))=a

But
up(down(b))=a
whereas
identity(b)=b

It's really mean to say someone isn't cute

Alternately, it is toxic to describe trolling behavior as 'cute' when it isn't, and hasn't been either cute or particularly witty or intelligent in a long time. This. Behavior. Is. Not. Cute.. It is lame.

0[anonymous]
The deliberate sabotage of threads? How cute will it be if he destroys the whole forum?

If dying after a billion years doesn't sound sad to you, it's because you lack a thousand-year-old brain that can make trillion-year plans.

If only the converse were true...

0Hawisher
"...if you lack a thousand-year-old brain that can make trillion-year plans, dying after a billion years doesn't sound sad to you"? I'm confused as to what you're trying to say. Are you saying that dying after a billion years sounds sad to you?

They aren't adding qualia, they are adding the utility they associate with qualia.

0Wrongnesslessness
It is not a trivial task to define a utility function that could compare such incomparable qualia. Wikipedia: Has it been shown that this is not the case for dust specks and torture?

What's more important to you, your desire to prevent genocide or your desire for a simple consistent utility function?

0Shmi
I thought it was clear in my post that I have no position on the issue. I was simply illustrating that a "consistent utility function" leads to a repugnant conclusion.

If you do happen to think that there is a source of morality beyond human beings... and I hear from quite a lot of people who are happy to rhapsodize on how Their-Favorite-Morality is built into the very fabric of the universe... then what if that morality tells you to kill people?

If you believe that there is any kind of stone tablet in the fabric of the universe, in the nature of reality, in the structure of logic—anywhere you care to put it—then what if you get a chance to read that stone tablet, and it turns out to say "Pain Is Good"? What t

... (read more)

Do not initiate intimate physical contact (hugs, touching shoulder, etc) unless the target has previously made similar contact with you.

If everyone follows this rule nobody will ever initiate physical contact.

5waveman
The only explanation for this is that it is acceptable for women to initiate physical contact without prior contact by the other party. This is an unconscious double standard.
[anonymous]100

So, I know this funny little trick where you can verbalize a desire and seek explicit permission to act it out while taking care to make sure nothing about the situation seems especially likely to make the other party feel coerced or intimidated into giving an answer out of synch with their preferences. It basically involves paying attention, modelling the other person as an agent, deciding on that basis whether the request is appropriate (while noting the distinction between "appropriate" and "acceptable to the other person") and then... (read more)

For a better-phrased example of this rule, see the code of conduct from the OpenSF polyamory conference:

No touching other people without asking! (Or unless you already have that sort of relationship with them.) We really mean it. This means no random hands on knees, shoulders, etc. We know this is California and everyone hugs, but please do that awkward "wanna hug?" gesture before actually hugging. When in doubt about any kind of social or erotic touching, please ASK FIRST. We have attendees who do not like to be touched, and they will like you much better if you respect their personal space.

I don't think a commonsense reading of this rule would prohibit holding one's arms up and saying "Hugs?"

-2TimS
4Douglas_Knight
Does the Slashdot system work well?

Genuine agreement with whimsical annoyance about having to consider actual situations and connotations.

0Decius
Thank you for the clarification.

Sounds good to me if you're going to get all connotative about it.

0Decius
Was that sour grapes with an ad-hom, genuine agreement with a condition, sarcasm, or something else? I honestly can't tell.

What about going from "members of subcategory X of category Y are more likely to possess characteristic C" to "In the absence of further information, a particular member of subcategory X is more likely to possess characteristic C than a non-X member of category Y".

You are saying you can't go from probabilistic information to certainty. This is a strawman.

3Decius
That only applies if there is an absence of further information. Do you make judgments about what the weather is right now by looking only at historical information, or do you look out the window? Also, if you're going to get into category theory: members of subcategory X of category Y are more likely to possess characteristic C Category A is a subset of category X Category B is mutually exclusive with category X, but a subset of Y Category B is smaller than category A Given only "members of subcategory X of category Y are more likely to possess characteristic C", can you draw a conclusion about whether a random member of category A or category B is more likely to possess characteristic C? Let characteristic C be "will perform above the 75th percentile of CEOs", category X be 'males', category A be 'males who being seriously considered for a CEO position', and category B be 'females and intersex people being considered for a CEO position'. It's only a strawman if it isn't the exact argument being used in the boardroom.

I wrote my comment above under the assumption of mjgeddes' honesty but I also believe they are more likely lying than not lying.

My alternative theories are: mjgeddes is just trolling without any real plan (40%), mjgeddes is planning to laugh at us all for believing something with such an explicitly low prior. (40%), something else (>19%), actually won the lottery: <1%

Yet still I feel the need to give them the benefit of the doubt. I wonder precisely when that social heuristic should be abandoned...

http://lesswrong.com/lw/sc/existential_angst_factory/

You could try self-modifying to not hate evil people ("hate the sin not the sinner"). Here's some emotional arguments that might help (I make no claim as to their logical coherence):

If there was only one person in existence and they were evil, would you want them to be punished or blessed? Who would it serve to punish them?

If you are going to excuse people with mental illness you are going to have to draw some arbitrary line along the gradient from "purposely evil" to "evil becau... (read more)

(bit of irony here :P)

Perhaps acceptable casualties.

I just won the New Zealand national lottery.

Congratulations!

For the sake of people reading this post who may not be familiar with the concept of backwards causality:

As a fun test, I called on any future super intelligences to come to my aid, appealing to the notion of backward causality. Asking for clear evidence of the hand of a superintelligence in the event I won, I choose a number of high significance to me personally. The number I chose was 27, which I placed in all lines of the ticket. (All the other numbers I selected at random).

This is not ... (read more)

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