Decision theory is not one of my strengths, and I have a question about it.
Is there a consensus view on how to deal with the problem of "rival formalizations"? Peterson (2009) illustrates the problem like this:
Imagine that you are a paparazzi photographer and that rumour has it that actress Julia Roberts will show up in either New York (NY), Los Angeles (LA) or Paris (P). Nothing is known about the probability of these states of the world. You have to decide if you should stay in America or catch a plane to Paris. If you stay and [she] shows up in Paris you get $0; otherwise you get your photos, which you will be able to sell for $10,000. If you catch a plane to Paris and Julia Roberts shows up in Paris your net gain after having paid for the ticket is $5,000, and if she shows up in America you for some reason, never mind why, get $6,000. Your initial representation of the decision problem is visualized in Table 2.13.
Table 2.13
P | LA | NY | |
Stay | $0 | $10k | $10k |
Go to Paris | $5k | $6k | $6k |
Since nothing is known about the probabilities of the states in Table 2.13, you decide it makes sense to regard them as equally probable [see Table 2.14].
Table 2.14
P (1/3) | LA (1/3) | NY (1/3) | |
Stay | $0 | $10k | $10k |
Go to Paris | $5k | $6k | $6k |
The rightmost columns are exactly parallel. Therefore, they can be merged into a single (disjuntive) column, by adding the probabilities of the two rightmost columns together (Table 2.15).
Table 2.15
P (1/3) | LA or NY (2/3) | |
Stay | $0 | $10k |
Go to Paris | $5k | $6k |
However, now suppose that you instead start with Table 2.13 and first merge the two repetitious states into a single state. You would then obtain the decision matrix in Table 2.16.
Table 2.16
P | LA or NY | |
Stay | $0 | $10k |
Go to Paris | $5k | $6k |
Now, since you know nothing about the probabilities of the two states, you decide to regard them as equally probable... This yields the formal representation in Table 2.17, which is clearly different from the one suggested above in Table 2.15.
Table 2.17
P (1/2) | LA or NY (1/2) | |
Stay | $0 | $10k |
Go to Paris | $5k | $6k |
Which formalisation is best, 2.15 or 2.17? It seems question begging to claim that one of them must be better than the other — so perhaps they are equally reasonable? If they are, we have an example of rival formalisations.
Note that the principle of maximising expected value recommends different acts in the two matrices. According to Table 2.15 you should stay, but 2.17 suggests you should go to Paris.
Does anyone know how to solve this problem? If one is not convinced by the illustration above, Peterson (2009) offers a proof that rival representations are possible on pages 33–35.
It's another form of the Bayesian priors problem, which I believe is fundamentally unsolvable. A Solomonoff prior gets you to within a constant factor, given sufficient computational resources, but that constant factor is allowed to be huge. You can drive the problem out from specific domains by gathering enough evidence about them to overwhelm the priors, but with a fixed pool of evidence, you really do have to just guess.
Regarding a set of states as equally probable is significant not for scientific or decision-theoretic reasons, but because it's a Schelling point in debates over priors. Unfortunately, as you have noticed, there can be arbitrarily many Schelling points, and the number of points increases as you add more vagaries to the problem. There are special cases in which you can derive an ignorance prior from symmetry - such as if the labels on the locations were known to have been shuffled in a uniformly random way - but the labels in this case are not symmetrical.